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Àð¸ðP(Iz   R„F f3+س/.aqLØiHjjjGGG      ^nðì2ð$&Îg§+yc_»öÆÔÏÿ0ó2ð$ïóù±?´Åk~Ïáj–«¸•ÿ0ó2ð$uǨUÁ(0Äzg5BG‰Vÿ%Móð$ÿóð$ÿóð$ÿóð$ÿóð$ÿóð$ÿóð$ÿóð$ÿóð$ÿóð$ÿóð$ÿó2ð$õŽ¡}|n­ÓÛ»1êÿÛ r0óð$ÿó2ð$„òm:lÁ8êÊßMTÐ>?ÿ M<óƒ ð0�ƒ†A¿ÀÅAÿPñ»Ù'µ/µÿÿÿf@ñÿÿ÷ð8ó€ó€Ðw]BÏÊš;­”ÇÊš;úgþý4KdKdì 0pÚŒÄÿÿÿpûppû@ <ý4dddd® 0,Þ¸3Úÿ <ý4!d!dœÚ.� 0,Þˆ8Š0º___PPT10‹ pµpµ?Ù Ú %ðZ-óŸ¨JOn the Existence of Multicolored Parallelisms of Isomorphic Spanning Trees¡KKŸ¨XHung-Lin Fu and Y. H. Lo Department of Applied Mathematics NCTU, Hsin Chu, Taiwan 30050 ¡&YXÿþª"AóŸ¨ PreliminariesŸ  A proper k-edge coloring of a graph G is a mapping from E(G) into {1,& ,k} such that incident edges of G receive distinct colors.¡t„‚ ‚‚‚9ó=Ÿ¨Facts on Edge-ColoringsŸ NLet G be a simple graph with maximum degree Dð(G). Then, the minimum number of colors needed to properly color G, cð¢ð(G), is either Dð(G) or Dð(G) + 1. (Vizing s Theorem) G is of class one if cð¢ð(G) = Dð(G) and class two otherwise. Kn is of class one if and only if n is even. Kn,n is of class one. ¡T(,¸‚Šçÿ,‚Šçÿ‚ªF•F*ó> Ÿ¨Rainbow Subgraph¡Vµ/µþ ªŸ¨vLet G be an edge-colored graph. Then a subgraph whose edges are of distinct colors is called a rainbow subgraph of G. It is also known as a heterochromatic subgraph or a multicolored subgraph. Note that the edge-coloring of the edge-colored graph may not be proper. In this talk, all edge-colorings are proper edge-colorings. Therefore, a rainbow star can be found easily.¡^wZ`; ÿþLnªP( 7 ·ó?!Ÿ¨Rainbow 1-factorŸ¨‡Theorem(Woolbright and Fu, JCD 1998) In a (2m-1)-edge-colored K2m where m > 2, there exists a rainbow 1-factor. (The coloring is arbitrarily given.) Conjecture(Transversal) In an n-edge-colored Kn,n, there exists a rainbow 1-factor for each odd integer n. (The coloring is arbitrarily given.) Note: There exist n-edge-colorings of Kn,n such that n edge-disjoint rainbow 1-factors exist. ¡îˆZÿþ çÿ"## ÿþ  çÿ:#) çÿ4ª> ³‡7ó@"Ÿ¨Multicolored Subgraphª Ÿ¨€ Given an (n-1)-edge-colored Kn, a multicolored Hamiltonian path exists for n > 4.(!?) How about multicolored spanning trees? ¡x€ˆçÿ€„ÿþ€ /€ª*aóA#Ÿ¨Orthogonal Latin SquaresŸ¨dA Latin square of order n corresponds to an n-edge-coloring of Kn,n. A Latin square of order n with an orthogonal mate provides n edge-disjoint multicolored 1-factors of Kn,n. 1 2 3 1 2 3 2 3 1 3 1 2 3 1 2 2 3 1 ¡n°ZµZ@ çÿh çÿ#ÿþÿþÿþ ÿþÿþ ÿþ ÿþª>?iœóC%Ÿ¨ Room SquaresŸ¨�A Room square of side 2m-1 provides a (2m-1)-edge-coloring of K2m such that 2m-1 edge- disjoint multicolored 1-factors exist. 35 17 28 46 26 48 15 37 13 57 68 24 47 16 38 25 58 23 14 67 12 78 56 34 36 45 27 18 ¡ü~ZZZ? çÿZ ÿfþ µ/µþÿþóB$Ÿ¨Multicolored Tree ParallelismŸ¨»K2m admits a multicolored tree parallelism (MTP) if there exists a proper (2m-1)-edge-coloring of K2m for which all edges can be partitioned into m isomorphic multicolored spanning trees.¡†¼çÿ ‚ÿþƒÿþÿþ2çÿ/ ÿþÿþóD&Ÿ¨K6 admits an MTP¡$çÿŸ¨š T1 T2 T3 Color 1: 35 46 12 Color 2: 24 15 36 Color 3: 25 34 16 Color 4: 26 13 45 Color 5: 14 23 56¡¤›çÿçÿçÿ       óŸ¨Three Conjectures on MTPŸ ¶ Constantine s Weak Conjecture For any natural number m>2, there exists a (2m-1)-edge-coloring of K2m for which K2m can be decomposed into m multicolored isomorphic spanning trees. (MTP) ¡„Üÿþ‚*çÿçÿ‚)óŸ¨ Brualdi-Hollongsworth Conjecture¡!!$ª Ÿ¨  If m>2, then in any proper edge coloring of K2m with 2m-1 colors, all edges can be partitioned into m multicolored spanning trees. ¡PŸ3çÿióŸ >Constantine s Strong Conjecture¡ $ÿþŸ¨§ If m>2, then in any proper edge coloring of K2m with 2m-1 colors, all edges can be partitioned into m isomorphic multicolored spanning trees. ¡X§2çÿ8 0ó Ÿ¨Theorem (Constanine, 2002)¡   ª Ÿ „ If m ¹ð 1 or 3 and K2m admits an MTP, then for all positive integer r > 1, admits an MTP. Lemma K12 admits an MTP. Thanks, Peter Cameron, Gap software works! There exists a proper edge coloring of K6,6 with 6 colors in which all edges can be partitioned into 6 multicolored subgraphs isomorphic to K1,3Èð3K2 Èð2K1.¡CZ‚  çÿ0"( çÿ,ÿþ( çÿb çÿ‚Šçÿ‚Šçÿ‚ª" ó Ÿ¨$Theorem (Akbari, Alipour, Fu and Lo)¡ % ÿþª, Ÿ à For m is an odd positive integer, then K2m admits an MTP. Corollary. Constantine s Weak Conjecture is true.¡:q+çÿ )óŸ¨Proof of the Main ResultŸ An m-total-coloring of a graph G is a mapping from V(G)ÈðE(G) into {1,2,3, & , m} such that incident vertices and edges receive distinct images.¡D�‚$W‚ó$ Ÿ¨An example: m = 5¡(Ÿ¡Zª ó%Ÿ¨An example: m = 5Ÿ¡Zª óH'Ÿ¨An example: m = 5Ÿ¡Zª óI(Ÿ¨An example: m = 5Ÿ¡Zª ó*Ÿ¨An example: m = 5Ÿ¡‚ª ó-Ÿ¨An example: m = 5Ÿ¡‚ª ó1Ÿ¨An example: m = 5Ÿ¡Z‚ª ó2Ÿ¨An example: m = 5Ÿ¡‚ª ó3Ÿ¨An example: m = 5Ÿ¡‚ª ó4Ÿ¨An example: m = 5Ÿ¡Zª óJ)Ÿ¨Concluding RemarkŸ –If the edge-coloring is arbitrarily given, then the proof of finding MTP is going to be very difficult. We may drop  isomorphism for the above case and find m multicolored spanning trees of K2m. 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Lo      . 33Ì.92 êã!Department of Applied Mathematics      . 33Ì.2 NCTU,  . 33Ì.2 gHsin Chu . 33Ì.2 å, Taiwan 30050  .--û¼ˆ"System 0-ð&TNPP &ÿÿÿÿþÿÕÍÕœ.“—+,ù®0܈�¤´¼ÄÌ Ô Üä ìôü  ^¶ ¦p¿Ã¹õ¤j¤pmychatj³òpí "Arial ·s²Ó©úÅéTahoma WingdingsSymbolBlendsMicrosoft ¤èµ{¦¡½s¿è¾¹ 3.0KOn the Existence of Multicolored Parallelisms of Isomorphic Spanning TreesPreliminariesFacts on Edge-ColoringsRainbow SubgraphRainbow 1-factorMulticolored SubgraphOrthogonal Latin Squares Room SquaresMulticolored Tree ParallelismK6 admits an MTPThree Conjectures on MTP!Brualdi-Hollongsworth Conjecture!Constantine¡¦s Strong ConjectureTheorem (Constanine, 2002)%Theorem (Akbari, Alipour, Fu and Lo)Proof of the Main ResultAn example: m = 5An example: m = 5An example: m = 5An example: m = 5An example: m = 5An example: m = 5An example: m = 5An example: m = 5An example: m = 5An example: m = 5Concluding Remark  ¨Ï¥Î¦r«¬ ²³ø³]­p½d¥»¤º´O OLE ¦øªAµ{¦¡ §ë¼v¤ù¼ÐÃDö_À‘㢳ôÚhlfuhlfu þÿÿÿ!"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~€�‚ƒ„…†‡ˆ‰Š‹Œ�Ž��‘’“”•–—˜™š›œ�žŸ ¡¢£¤¥¦§¨©ª«¬­®¯°±²³´µ¶·¸¹º»¼½¾¿ÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖרÙÚÛÜÝÞßàáâãäåæçèéêëìíîïðñòóôõö÷øùúûüýþÿ      !"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyþÿÿÿ{|}~€�‚ƒ„…†‡ˆ‰Š‹Œ�Ž��‘’“”•þÿÿÿ—˜™š›œ�þÿÿÿŸ ¡¢£¤¥þÿÿÿýÿÿÿýÿÿÿýÿÿÿýÿÿÿ«þÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿRoot Entryÿÿÿÿÿÿÿÿ��d›Oφꪹ)èþÿÿÿPicturesÿÿÿÿÿÿÿÿÿÿÿÿí>Current UserÿÿÿÿÿÿÿÿžSummaryInformation(ÿÿÿÿzÌ6PowerPoint Document(ÿÿÿÿÿÿÿÿÿÿÿÿ ƳDocumentSummaryInformation8ÿÿÿÿÿÿÿÿ–ÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿ